为何进不了ARM的串口中断？（有注释）
为什么进不了ARM的串口中断编译工具：IAR For ARM
芯片：LPC2103
ps:程序中的
UART0_GetChar() UART0_GetString() UART0_PutChar() UART0_PutString()这些函数都是可以正常使用，可以正常串口接收发送程序。但就是进不了串口接收中断
#include "iolpc2103.h"
#include "config.h"
#include "lpc2103.h"
#define UART_BPS 9600 //波特率9600
unsigned char rcv_new=0;
//---------------------串口0的中断服务程序------------------
void Uart0Handler(void)
{
rcv_new = 1; //将自定义的串口中断标志变量置1（在主函数中用到此变量）
VICVectAddr0 = 0; //清除中断地址向量
}
//-------------------串口0的中断初始化-----------------
void UART0_Interrupt_Init(void)
{
VICIntSelect = 0x00000000; //将所有的中断选择为IRQ模式
VICVectCntl0 = 0x26; //向量IRQ使能且选择对应的UART0中断号 0x26 = 0x02|0x06;
VICVectAddr0 = (unsigned int)Uart0Handler; //将中断服务程序的地址装载到VICVectAddr0地址向量中
VICIntEnable = 1<<6; //UART0串口中断使能
}
//-------------------------------------------------------
#pragma vector=IRQV
__irq __arm void irq_handler (void)
{
void (*interrupt_function)();
unsigned int vector;
vector = VICVectAddr0;
interrupt_function = (void(*)())vector;
if(interrupt_function != '\0')
{
interrupt_function();
}
else
{
VICVectAddr = 0;
}
}
//-------------------串口0初始化-------------------
void UART0_Init ()
{
U16 Fdiv;
U0LCR = 0x83;//打开“除数修改”
Fdiv = (Fpclk / 16)/ UART_BPS;
U0DLM = Fdiv / 256;
U0DLL = Fdiv % 256;
U0LCR = 0x03;//关闭“除数修改”
U0FCR = 0x81;//选择触发点0（1个字符或0x01h）+FIFO使能
U0IER = 0x01;//RBR（串口接收中断）使能
}
//----------------串口0发送1个byte----------------------
void UART0_PutChar ( chardata)
{
U0THR = data;
while( (U0LSR&0x40)==0 );
}
//----------------串口0发送字符串----------------
UART0_PutString(unsigned char *str)
{
while(*str!='\0')
{
UART0_PutChar(*str++);
}
}
//-----------------串口0接收1个byte---------------
char UART0_GetChar ( void )
{
unsigned char Rcv_Data;
while((U0LSR&0x01)==0);
Rcv_Data=U0RBR;
return(Rcv_Data);
}
//----------------串口0接收字符串---------------
void UARt0_GetString(unsigned char *str, unsigned char n)
{
for(;n>0;n++)
{
*str++=UART0_GetChar();
}
}
//------------PLL（锁相环）初始化-----------------
void PLL_Init(void)//PLL init function
{
PLLCON = 1;// PLL enable
#if ((Fcclk / 4) / Fpclk) == 1//
VPBDIV = 0;
#endif
#if ((Fcclk / 4) / Fpclk) == 2
VPBDIV = 2;
#endif
#if ((Fcclk / 4) / Fpclk) == 4
VPBDIV = 1;
#endif
#if (Fcco / Fcclk) == 2
PLLCFG = ((Fcclk / Fosc) - 1) | (0 << 5);
#endif
#if (Fcco / Fcclk) == 4
PLLCFG = ((Fcclk / Fosc) - 1) | (1 << 5);
#endif
#if (Fcco / Fcclk) == 8
PLLCFG = ((Fcclk / Fosc) - 1) | (2 << 5);
#endif
#if (Fcco / Fcclk) == 16
PLLCFG = ((Fcclk / Fosc) - 1) | (3 << 5);
#endif
PLLFEED = 0xaa;//fixed don't change
PLLFEED = 0x55;//fixed don't change
while((PLLSTAT & (1 << 10)) == 0);//when PLOCK=1,PLL is locked
PLLCON = 3;//when PLLFEED is ok, PLL works
PLLFEED = 0xaa;//fixed don't change.
PLLFEED = 0x55; //fixed don't change
}
//---------------------主函数--------------------
void main(void)
{
char temp = '0';
PINSEL0 = (PINSEL0 & (~0x03))|(0x01);
PINSEL0 = (PINSEL0 & (~(0x03<<2))|(0x01<<2));
PLL_Init();
UART0_Init();
UART0_Interrupt_Init();
UART0_PutString("Init success");
while(1)
{
if(rcv_new == 1)//程序运行后，无论用串口调试助手怎么发送数据，都进不了串口接收中断，程序总是停留在这一行
{
UART0_PutString("I success,haha~!");
rcv_new = 0;
}
}
} 顶 弱弱的问句楼主，LPC21**的外部中断你会吗，我今天弄了一天快要疯了，要是会的话，求留个QQ讨论下，我QQ923996994，最好能讨论下才有结果嘛 顶 可能是你的串口0中断服务函数的名字取的不对，好像有 专门的格式，你改成void __irq IRQ_UART0()
或者void UART0_IRQHandler() 试一下
页:
[1]