LPC2368 中斷
小弟經過多次調試,還是無法實現中斷中斷是低電平觸發 EINT1 P2.11
當P2.11 接地的時候 程序在LPC2300.S 跑
開發程式是UVISION4 用JLINKV8調試
以下是其中一段程序
LPC2300.S
; Exception Vectors
;Mapped to Address 0.
;Absolute addressing mode must be used.
;Dummy Handlers are implemented as infinite loops which can be modified.
Vectors LDR PC, Reset_Addr
LDR PC, Undef_Addr
LDR PC, SWI_Addr
LDR PC, PAbt_Addr
LDR PC, DAbt_Addr
NOP ; Reserved Vector
; LDR PC, IRQ_Addr
LDR PC, ; Vector from VicVectAddr
LDR PC, FIQ_Addr
Reset_Addr DCD Reset_Handler
Undef_Addr DCD Undef_Handler
SWI_Addr DCD SWI_Handler
PAbt_Addr DCD PAbt_Handler
DAbt_Addr DCD DAbt_Handler
DCD 0 ; Reserved Address
IRQ_Addr DCD IRQ_Handler
FIQ_Addr DCD FIQ_Handler 當中斷發生後,不停的重復執行這句
Undef_Handler B Undef_Handler
SWI_Handler B SWI_Handler
PAbt_Handler B PAbt_Handler
DAbt_Handler B DAbt_Handler
IRQ_Handler B IRQ_Handler
FIQ_Handler B FIQ_Handler
; Reset Handler
EXPORTReset_Handler
Reset_Handler
主程序
void clkinit(void)
{
PLLCON=0;/* disconnect and disable*/
PLLFEED=0xAA;/*PLL FEED*/
PLLFEED=0x55;
CLKSRCSEL=0x01;/*ETC source 12Mhz*/
PLLCFG=((0x0<<16)|(0x0B));/*N=1 M=12 FCC0=288Mhz*/
PLLFEED=0xAA;/*PLL FEED*/
PLLFEED=0x55;
PLLCON=0x01;/* disconnect and ENable*/
PLLFEED=0xAA;/*PLL FEED*/
PLLFEED=0x55;
CCLKCFG=0x02;/*divide by 24CCLK=96Mhz*/
while((PLLSTAT & 0x4000000)==0);/* wait until PLOCK = 1 */
PLLCON=0x03;/* disconnect and ENable*/
PLLFEED=0xAA;/*PLL FEED*/
PLLFEED=0x55;
PCLKSEL1=((0x01<<28)|(0x01<<4)|(0x01<<2));/*GPIO,CONNECT BLOCK,CONTROL BLOCK F=CCLK */
}
void intinit (void)
{
FIO2DIR=((1<<1)|(1<<0));
FIO2CLR=0x03;
FIO2SET=0x03;
PINSEL4=(1<<22);/*Block connect EINT1*/
VICVectPriority0 = 0;
VICVectAddr0 = (unsigned)test;
VICIntSelect=(1<<15);
VICIntEnable=(1<<15);
__enable_irq();
}
void test (void) __irq
{
FIO2CLR = 0x03;
pant(0x1f);
EXTINT = 0x02;
VICVectAddr = 0x00000000;
}
int main (void)
{
clkinit();
intinit();
IODIR0=0XFFFFFFFF;
IOCLR0=0XFFFFFFFF;
while(1);
} 問題己解決,因為EINT1一定要用VICVectAddr15 和 ICVectPriority15 问LZ个问题，这里干嘛要先清零再写一？
FIO2CLR=0x03;
FIO2SET=0x03;
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