4*4按键简单程序
谁来帮我看看下面这个程序，很简单的
#include <msp430x14x.h>
unsigned char temp,key=0;
#define keyin (P1IN & 0x0f)
const unsigned char aa[]={ 0x3F,
0x06,//"1"
0x5B,//"2"
0x4F,//"3"
0x66,//"4"
0x6D,//"5"
0x7D,//"6"
0x07,//"7"
0x7F,//"8"
0x6F,//"9"
0x77,//"A"
0x7C,//"B"
0x39,//"C"
0x5E,//"D"
0x79,//"E"
0x71};
void delay(unsigned char z);
int main( void )
{
WDTCTL = WDTPW + WDTHOLD;
P2DIR |= 0xff;
P2OUT = aa;
P1DIR = 0xf0;
//OUT = 0x00;
// P1DIR |= 0xf0;
// P1OUT =0x0f;
// temp = P1OUT ;
// temp &= 0x0f;
while(1){
if (keyin != 0x0f){
delay(5);
if (keyin != 0x0f){
temp = keyin;
while(keyin != 0x0f);
switch(temp){
case 0x0e:key=0;
break;
case 0x0d:key=1;
break;
case 0x0b:key=2;
break;
case 0x07:key=3;
break;
default: P2OUT ^= BIT7;
}
P2OUT = aa;
}
}
}}
void delay(unsigned char z)
{unsigned int x;
for(x=z;x>0;x--);
} 回复【楼主位】12521843
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按键没有任何反应，
不知什么地方那个搞错了
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