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luo_12yan 发表于 2009-6-9 20:45:01

布尔表达式化简—求教

f=x1x3+x1!x2+!X1X2x3+!x1!x2!x3

f=(x1+x2+x3)(x1+!x2+x3)(!x1+!x2+x3)(x1+x2+!x3)

f=!x1!x2x3+!x1x2!x3+!x1x2x3+x1!x2!x3+!x1!x2!x3

希望能写出化简过程

gutao007 发表于 2009-6-10 15:46:55

帮你第一个,其余自己来:
= (x1x3 + /x1x2x3)+(x1/x2+/x1/x2/x3)
= x3(x1+/x1x2)+/x2(x1+/x1/x3)
= x3(x1+x2)+/x2(x1+/x3)
= x1x3+x2x3+x1/x2+/x2/x3
= (x1/x2+x2x3+x1x3)+/x2/x3
= x1/x2+x2x3+/x2/x3

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